tag:blogger.com,1999:blog-4519238203196996408.post4166768155125490810..comments2017-06-09T15:33:17.661-07:00Comments on The Hydra's Grotto: In Praise of the 6 Mile HexSteamtunnelhttp://www.blogger.com/profile/02597332921872904036noreply@blogger.comBlogger25125tag:blogger.com,1999:blog-4519238203196996408.post-87342073959455172832017-03-08T02:40:08.223-08:002017-03-08T02:40:08.223-08:00@Bradon - A 6 mile hex is actually 31 square miles...@Bradon - A 6 mile hex is actually 31 square miles, not 24. To get that area, you'd need a five-and-quarter mile hex.GamesBookhttps://www.blogger.com/profile/08822273243607808813noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-51354578215862567392016-12-08T11:50:14.485-08:002016-12-08T11:50:14.485-08:00This is so amazing! Thank you! This is so amazing! Thank you! Red_Five_Standing_byhttps://www.blogger.com/profile/07193459687911010055noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-20327468797566054542016-03-30T06:09:22.890-07:002016-03-30T06:09:22.890-07:00Hi there,
I'm new to hexcrawling & sandbox...Hi there,<br />I'm new to hexcrawling & sandboxing in general, and your blog (this post) is constantly linked to whenever people talk about learning about hexcrawling. I'm working on a campaign that should span the party around 3 months of in-game time, and I'm wanting to present it as a hexcrawl. My idea is to create the size/scale of the campaign region based around that. That gives me roughly 90 in-game days to work with. <br /><br />If I want the party to reasonably be able to explore 1 full hex in a day (assuming no adverse conditions, so they're all healthy, not trudging through swamps, etc), it looks to me like the 6 mile hex should be good for that (since a 6 mile hex is just slightly less than 24 square miles) - in fact, if they were in a plains area and could see all around, I would assume the could do it in much less time than a day. Is this reasonable for me to assume?<br /><br />Thanks!Brandon Daggerharthttps://www.blogger.com/profile/03965986442476126755noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-6903918475289952082016-02-04T14:56:12.898-08:002016-02-04T14:56:12.898-08:00If anyone wanted to know ('cause I did!) the a...If anyone wanted to know ('cause I did!) the area of the 6 mile hex. is: 31.82643359m2. <br /><br />A hex is 6 Equilateral Triangles, the base and sides are 3.5, so I figured out the height:<br /><br />3.5xCos30 = 3.031088913<br /><br />Then to find the area of each Triangle:<br /><br />1/2x3.5x3.031088913 = 5.304405598<br /><br />Multiplied that by 6 for the full area of the hexagon:<br /><br />5.304405598x6 = 31.82643359m2 per 6 mile hex.<br /><br />OR if you replace the 3.5 with the actual 3.49 as it should be, the answer becomes: 31.64482806m2<br /><br />And someone please correct this if it's wrong <3Daniel McLoughlinhttps://www.blogger.com/profile/17260633905350936642noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-31528278644602141812015-09-11T08:29:33.724-07:002015-09-11T08:29:33.724-07:00How do you break the hex down into more hexes? Sur...How do you break the hex down into more hexes? Surely they won't fit without overlapping with another hex?RMcD94https://www.blogger.com/profile/16919280566803775512noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-72355818695175705222015-05-17T17:55:08.564-07:002015-05-17T17:55:08.564-07:00I keep coming back to this post and rereading it b...I keep coming back to this post and rereading it because it is so tracking cool and makes such sense. Thanks for it.Dale Himebaughhttps://www.blogger.com/profile/04784778921530575525noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-48126756525673157712015-03-26T10:39:42.444-07:002015-03-26T10:39:42.444-07:00I'm sold on 6 mile hexes.
I looked up distan...I'm sold on 6 mile hexes. <br /><br />I looked up distance and I get this<br /><br />if we figure earth with an atmosphere then d= 1.32(sqrt(h))<br /><br />d=statue miles<br />h= feet.<br /><br />close enough anyways.Brian Sommershttps://www.blogger.com/profile/14172786513198005125noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-67304112324415412542014-09-07T03:35:08.282-07:002014-09-07T03:35:08.282-07:00Can you suggest a graph paper that lets you do the...Can you suggest a graph paper that lets you do the 12 mile super hex well?Zombie Neighbourshttps://www.blogger.com/profile/07175770925377086853noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-72644029498625832972014-07-24T14:21:18.570-07:002014-07-24T14:21:18.570-07:00Very cool, steamtunnel. I'm especially intere...Very cool, steamtunnel. I'm especially interested in the horizon calcluations. I think your recommendations might be a bit short, given the horizon calculations on the wikipedia page.<br /><br />A 1,000-foot prominence (a large hill, half the size of the smallest mountain, by one definition) is visible from 38 miles away, which is roughly 6.5 6-miles hexes.<br /><br />A 9,000-foot prominence (which is roughly the distance that Everest towers above its base camp), is visible from 19 hexes away!<br /><br />Now, all I'm doing to get these numbers is to assume that you can see anything that can see you.<br /><br />Oh, actually, I see I'm doing that wrong. According to WP, the way to tell the distance to tall objects is to add together the observer's to-the-horizon distance with that of a hypothetical, second observer, atop the thing you're trying to see.<br /><br />So if you're on a 1,000-foot prominence trying to see a 9,000 foot prominence, you can see that from 6.5+19=25.5 hexes away. (Woah.)Michael Prescotthttps://www.blogger.com/profile/04704966067758312492noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-33166562886372091012013-11-03T12:56:22.194-08:002013-11-03T12:56:22.194-08:00I would break the 6 mile hex down into six 1 mile ...I would break the 6 mile hex down into six 1 mile hexes. After that, I would break that down into 8 furlong hexes.<br /><br />On the encounter level, I would use the fathom, which is the length from one finger tip to the other if you hold your hands out (measured as 6 foot).<br /><br />The basic unit of measure for land in the medieval period was the Furlong. It is 1/8th of a mile. 660 feet. 220 yards.<br /><br />110 fathom hexes would make up one furlong. You could use any typical battlemat with that system.Steve Reeveshttps://www.blogger.com/profile/16869676716891199486noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-81772105535888160122013-09-25T07:56:18.011-07:002013-09-25T07:56:18.011-07:00Great article that has been part of my bookmarks f...Great article that has been part of my bookmarks for quite some time now. I am posting this comment however with a question : would you mind if I use your article in a adventure supplement (released under Creative Commons) I am working on? With recognition of your authorship of course. Arnehttps://www.blogger.com/profile/00785136959461712512noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-88938857644917024712013-02-18T08:28:24.482-08:002013-02-18T08:28:24.482-08:00I find this information very useful. Thank you for...I find this information very useful. Thank you for posting. DuBeershttps://www.blogger.com/profile/12770517741281593733noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-47913130628839193782013-01-02T15:39:48.988-08:002013-01-02T15:39:48.988-08:00*slurp*
These. Good.*slurp*<br /><br />These. Good.Brett Slocumhttps://www.blogger.com/profile/09240226222507995367noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-90513607279904143472012-03-31T21:57:39.841-07:002012-03-31T21:57:39.841-07:00@2097 you need to re-read. You are correct, 7^2-6^...@2097 you need to re-read. You are correct, 7^2-6^2 does not = 3.5^2<br /><br />And 6.98^2 - 6^2 does not = 3.49^2<br /><br />That is because these numbers are longer decimals that have been rounded up to the nearest 100th of a mile (or 52.8 ft). What you need to do is start with a 6 mile line and then determine what the lengths of an equalateral triange with a height of 3 is. This will get you the more precise numbers you so eagerly desire.Steamtunnelhttps://www.blogger.com/profile/02597332921872904036noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-38000481694367906692012-03-27T13:06:42.545-07:002012-03-27T13:06:42.545-07:00I don’t get the math.
7² - 6² ≠ 3.5²I don’t get the math.<br /><br />7² - 6² ≠ 3.5²2097https://www.blogger.com/profile/18418864370687617212noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-11929531624093015982011-12-15T17:28:00.425-08:002011-12-15T17:28:00.425-08:00Even later to the party, but just as grateful. Tha...Even later to the party, but just as grateful. Thanks! :)John Adamshttps://www.blogger.com/profile/16019288193878283384noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-45146432615042304202011-03-24T18:50:56.320-07:002011-03-24T18:50:56.320-07:00Late to the party, but this is a great idea and we...Late to the party, but this is a great idea and we're going to adopt it for our maps from now on. This is a sensible, and effective standard. If the D30 gets a whole Order promoting it, then the Six Mile Hex ought to have some sort of icon or whatever as well, don't you think?NetherWerkshttps://www.blogger.com/profile/08361800925618339097noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-54218422021662554322010-06-09T15:33:14.290-07:002010-06-09T15:33:14.290-07:00I keep coming back just for this post. You've ...I keep coming back just for this post. You've made your stamp on my campaign map.<br /><br />Confirmation: recorate, what Shaggy did, like, to his pad, man.Dangerhttps://www.blogger.com/profile/14825849684370091427noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-23140672382124463602010-02-22T04:32:36.402-08:002010-02-22T04:32:36.402-08:00A quick calculation shows that a 6-mile hex is als...A quick calculation shows that a 6-mile hex is also within 0.3% of being 20,000 acres.<br /><br />I think we have a winner.Nagorahttps://www.blogger.com/profile/04934827653905274555noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-39832542621816212592009-12-30T16:58:46.222-08:002009-12-30T16:58:46.222-08:00This is awesome. I'm working on a hex crawl ri...This is awesome. I'm working on a hex crawl right now, but I'm very afraid of how much work it's going to be to map out the next hex depth down from my current map. If the smaller hexes are 6 miles, and 12 of those across is a world hex, I can set my world hex size to 72 miles. <br /><br />Will need some editing to make things closer together at that point. <br /><br />But what you've done here is lovely. Thanks!1d30http://1d30.wordpress.com/noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-19970175993458984042009-12-04T13:49:27.502-08:002009-12-04T13:49:27.502-08:00Marvelous. Thanks for laying this all out; it will...Marvelous. Thanks for laying this all out; it will be helpful to me very soon! (Isle of Dread, doncha know)...Jaysonhttps://www.blogger.com/profile/03652611193354218021noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-71752445716644533112009-12-04T13:49:27.501-08:002009-12-04T13:49:27.501-08:00Thanks for laying all this out!Thanks for laying all this out!Jaysonhttps://www.blogger.com/profile/03652611193354218021noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-27946843758764123202009-12-04T08:18:37.884-08:002009-12-04T08:18:37.884-08:00Thanks for the diagram -- very helpful. I think I...Thanks for the diagram -- very helpful. I think I'll need to think and write more about this.stirgessuckhttp://stirgessuck.wordpress.com/noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-47424904252298785242009-12-04T08:15:12.647-08:002009-12-04T08:15:12.647-08:00Once I get by breath back, and some dry pants, I a...Once I get by breath back, and some dry pants, I am totally printing out a copy of this mofo post and sticking it in my GM binder.<br /><br />THIS.<br /><br />IS.<br /><br /><b>AWESOME</b>Dr-Rotwanghttps://www.blogger.com/profile/16750632906878388570noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-47509412374260369062009-12-04T06:52:52.786-08:002009-12-04T06:52:52.786-08:00That is AWESOME.
FWIW, I double-checked the math,...That is AWESOME.<br /><br />FWIW, I double-checked the math, and you are indeed right. :)Geoffreyhttps://www.blogger.com/profile/16161800901863646891noreply@blogger.com