tag:blogger.com,1999:blog-4519238203196996408.comments2024-02-25T05:38:00.078-08:00The Hydra's GrottoSteamtunnelhttp://www.blogger.com/profile/02597332921872904036noreply@blogger.comBlogger131125tag:blogger.com,1999:blog-4519238203196996408.post-73091619357196521772020-09-14T14:20:46.850-07:002020-09-14T14:20:46.850-07:00Any chance of reuploading these? The links are dea...Any chance of reuploading these? The links are dead and I can't find anywhere else on the Internet with 6mi hex templates like you advocate so well for!Ariviahttps://www.blogger.com/profile/02562344254598570078noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-22534833136909851322020-08-01T15:51:26.394-07:002020-08-01T15:51:26.394-07:001. As someone else commented just above, I also no...1. As someone else commented just above, I also noticed using https://hexagoncalculator.apphb.com/ that the side/center-to-vertex lengths and vertex-to-vertex lengths aren't quite the values the blog posts claimed, but actually 3.46 and 6.92 miles. This isn't a particularly bad mistake, but a 5 mile hex has sides/side-to-vertex of 2.9 (so about 3) and vertex-to-vertex length of 5.8 (so about 6) miles when rounded to 1 decimal too, so it's not really that different.<br /><br />2. One could also argue that with the horizon of a flat plane being about 3 miles away for an observer at a height of 6 feet, a 5-mile hex is the better choice for a part being able to see from the edge (last half-mile or so) from the previous hex to the middle of the one they're about to enter. Or from the middle of the one they're in to the first half-mile or so of each neighbouring hex. In a 6-mile hex, in the middle they can *only* see their current hex. I would think that which option is better depends in part on if you want to use single-biome hexes or not, whether rivers and roads neatly follow hex borders (even subhex ones!), etc. And of course the average/maximum height of vegetation (if you're on a grassy plain where the grass is 3 feet high all over, a 6-foot observer is only observing from a height of 3 feet, and their horizon is 2.1 miles away), hills and other topography changes etc. likely matter much more how far something can be seen. In Fantasy RPGs, levitation (if you can control the altitude)/flight spells become very useful for mapping if you take observer height into account.<br /><br />3. Point 3 is basically meaningless, at least for just wanting half-mile subhexes. You could have a 5-mile hex which is 10 subhexes across instead of 6 and 12 and it would achieve the same thing. The rest of the math regarding 1/24 mile sub-subhexes (an arbitrary choice in itself) would work out the same.<br /><br />There's nothing wrong with 6 mile hexes, but it's not *that* superior to a 5-mile one either. Or most other sizes used in various games. I say use whatever works or is supported by the general travel, encounter, and other systems you're using. For example, Harnmaster uses 5-<i>league</i> hexes, and a league was/is customarily defined as about as much as a person walks in an hour, about 2.5 miles or 4 km (so a hex is 12.5 miles or 20 km). The travel system outlines travel in 4-hour intervals, and in that time 5 leagues is possible on roads or trails through flat areas, but not through cropland, forests, hilly terrain, etc. It doesn't use subhexes that I'm aware of, instead just mapping everything naturalistically, and showing a scale in addition to the 5-league hexes.<br /><br />And lastly, especially down at the level of 1/24 miles, things start getting really opaque for those of us more used to km. 1 mile is still "something more than 1.5 km" (1609 meters and change) and half a mile is "less than 1 km" (0.8 and change), but 1/24 needs a calculator. Another reason why I like Harnmaster's travel/distance, since it offers conversion ratios to both metric and US/Imperial, and doesn't strongly favour either (smaller-scale stuff mostly uses feet iirc). 5 miles is 8.05 km and 6 miles 9.66 km, but those 5:8 or 6:10(ish? 9.5? 5 miles may be slightly better here!) ratios are rarely mentioned in most mainstream or even indie RPG stuff due to the US standards dominating.unknown2https://www.blogger.com/profile/17767039287440123174noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-66728326045544558532020-05-11T17:55:17.784-07:002020-05-11T17:55:17.784-07:00Greetings!
The links seem to be down. Also, unde...Greetings! <br /><br />The links seem to be down. Also, under what license are you releasing these PDF templates?<br /><br />Thanks! Stripehttps://www.blogger.com/profile/03956310256102950543noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-11306640848955585812020-02-08T07:52:30.493-08:002020-02-08T07:52:30.493-08:00Haha! Clerks!Haha! Clerks!Anonymoushttps://www.blogger.com/profile/12581464573953072827noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-9568482900521478542020-01-28T12:42:22.033-08:002020-01-28T12:42:22.033-08:00I did the math, and this may not be perfect, heavy...I did the math, and this may not be perfect, heavy approximations and such, but the US is about 121,777 6-mile-hexes squared.Andrew Sawyerhttps://www.blogger.com/profile/15263056911810945780noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-27318750251211709242019-12-25T00:37:07.369-08:002019-12-25T00:37:07.369-08:00Links are dead, could you please reupload?Links are dead, could you please reupload?Roberthttps://www.blogger.com/profile/14970086692974535081noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-58886750547318414102018-10-26T19:25:47.585-07:002018-10-26T19:25:47.585-07:00I am only parroting what I've read before and ...I am only parroting what I've read before and can't remember from where (actually, I think I'm combining two notions that struck me as related), but here goes my thoughts about the cleric and the cleric's sub-game: It seems the distinctive class feature of the cleric is turn undead which uses 2d6. The other systems which use 2d6 are morale, retainer loyalty, and reaction. The later two may be affected by CHA, also alignment can also be a factor in the later two (and in some versions of turn undead as well). Thematically they all seem related to alignment and I think I've read it referred to as the alignment subsystem. There's no reason mechanically why a cleric would be better at reactions or loyalty, but fluff-wise it seems fitting. So I would posit alignment as the cleric's schtick. Also, since I never played AD&D back in the day, only Classic DnD, I think of the cleric first as an enemy of undead, only secondly as a healer (since spells didn't come into play till level 2).KingofElflandhttps://www.blogger.com/profile/01725335915535937373noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-6662879233074892452018-10-26T08:54:54.999-07:002018-10-26T08:54:54.999-07:00The dwarves were lost in the woods and literally s...The dwarves were lost in the woods and literally starving. They didn't do anything other than stumble into the elves while seeking assistance, and were locked up for it. Why? Because they refused to tell the elves why they were there. And frankly it wasn't the elves' business. The elves didn't own the entire woods and had no right to lock up anyone. Of course the dwarves didn't want to explain why they were there, because they knew the greedy elves would demand a cut of the treasure - a treasure they had absolutely no right to. That treasure belonged to the dwarves and was stolen by the dragon. A bunch of wood elves have absolutely no claim to a penny of it, especially after a) imprisoning the ones who actually owned it and b) showing up on the dwarves' doorstep with an army, making demands. The simple act of showing up with arms demanding loot is enough of a reason to tell them to shove off. <br /><br />As for the humans, it was foolish of the dwarves to not help them - it would have been favorable for the dwarves to do so, seeing as those same men would be the ones they would likely do their primary trading with - but legally speaking they didn't owe them jack. There was never at any time an agreement for any sort of payment or even an implication of such. And, like the elves, you show up with an army making demands and of course the rightful king is going to tell you to get lost. Once you show up at my house waving around a weapon we've gone past diplomacy.<br /><br />Oh, and that little Hobbit was a right bastard too. He effectively betrayed his companions, literally robbed them, all so that they would agree to give a bunch of treasure to the same elves who wrongfully imprisoned them all and then showed up on their front porch with an army demanding payment. Eff the elves and eff Bilbo, too.WilderChairshttps://www.blogger.com/profile/04415167602027165577noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-37854909580823966972018-09-14T01:11:10.429-07:002018-09-14T01:11:10.429-07:00Such as sherlock holmes noticing the clues of fres...Such as sherlock holmes noticing the clues of fresh plaster cement by the wall and a drop of spilled wine on it as clues that there is a recently crafted secret door actuated by the second coat hook (game of shadows).Sean Robert Meaneyhttps://www.blogger.com/profile/16273566549106707316noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-9338518490843678912018-02-02T16:11:03.487-08:002018-02-02T16:11:03.487-08:00Daniel, that's slightly incorrect. You assumed...Daniel, that's slightly incorrect. You assumed a 3.5 (or 3.49) mile side for your triangles to find the height, but that's only an approximate length based on the already known triangle height of 3 (hex width /2).<br /><br />Going with the height of 3, the sides are actually 6tan(30), or 3.464...<br /><br />I calculate the area to be 31.1769... sq.mi.<br /><br />Side note: vertex to vertex is 6/cos(30)= 6.9282...Anonymoushttps://www.blogger.com/profile/17550049209189568790noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-87342073959455172832017-03-08T02:40:08.223-08:002017-03-08T02:40:08.223-08:00@Bradon - A 6 mile hex is actually 31 square miles...@Bradon - A 6 mile hex is actually 31 square miles, not 24. To get that area, you'd need a five-and-quarter mile hex.GamesBookhttps://www.blogger.com/profile/08822273243607808813noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-51354578215862567392016-12-08T11:50:14.485-08:002016-12-08T11:50:14.485-08:00This is so amazing! Thank you! This is so amazing! Thank you! Red_Five_Standing_byhttps://www.blogger.com/profile/07193459687911010055noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-20327468797566054542016-03-30T06:09:22.890-07:002016-03-30T06:09:22.890-07:00Hi there,
I'm new to hexcrawling & sandbox...Hi there,<br />I'm new to hexcrawling & sandboxing in general, and your blog (this post) is constantly linked to whenever people talk about learning about hexcrawling. I'm working on a campaign that should span the party around 3 months of in-game time, and I'm wanting to present it as a hexcrawl. My idea is to create the size/scale of the campaign region based around that. That gives me roughly 90 in-game days to work with. <br /><br />If I want the party to reasonably be able to explore 1 full hex in a day (assuming no adverse conditions, so they're all healthy, not trudging through swamps, etc), it looks to me like the 6 mile hex should be good for that (since a 6 mile hex is just slightly less than 24 square miles) - in fact, if they were in a plains area and could see all around, I would assume the could do it in much less time than a day. Is this reasonable for me to assume?<br /><br />Thanks!brandon karlishttps://www.blogger.com/profile/03965986442476126755noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-75133076683242370532016-03-17T07:46:09.126-07:002016-03-17T07:46:09.126-07:00Brilliant ideas!Brilliant ideas!Jason Rhttps://www.blogger.com/profile/10308752560098089761noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-7096709712024370732016-02-16T22:37:23.706-08:002016-02-16T22:37:23.706-08:00Interesting read. I love what Chris at HC has don...Interesting read. I love what Chris at HC has done with pointcrawls; his recent update on Hexcrawls vs. Pointcrawls was a great read.Solabuscahttps://www.blogger.com/profile/11381511988030992581noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-6903918475289952082016-02-04T14:56:12.898-08:002016-02-04T14:56:12.898-08:00If anyone wanted to know ('cause I did!) the a...If anyone wanted to know ('cause I did!) the area of the 6 mile hex. is: 31.82643359m2. <br /><br />A hex is 6 Equilateral Triangles, the base and sides are 3.5, so I figured out the height:<br /><br />3.5xCos30 = 3.031088913<br /><br />Then to find the area of each Triangle:<br /><br />1/2x3.5x3.031088913 = 5.304405598<br /><br />Multiplied that by 6 for the full area of the hexagon:<br /><br />5.304405598x6 = 31.82643359m2 per 6 mile hex.<br /><br />OR if you replace the 3.5 with the actual 3.49 as it should be, the answer becomes: 31.64482806m2<br /><br />And someone please correct this if it's wrong <3Anonymoushttps://www.blogger.com/profile/17260633905350936642noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-69357472487070850922015-12-30T11:42:04.566-08:002015-12-30T11:42:04.566-08:00Totally going to make a 17.234534 strength charact...Totally going to make a 17.234534 strength character nowScott Andersonhttps://www.blogger.com/profile/12067161332003628237noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-35433276467213531332015-12-30T03:00:53.992-08:002015-12-30T03:00:53.992-08:00Good to have you back. I discovered your blog, whi...Good to have you back. I discovered your blog, while you were away. Your work on the Six Mile hex has been really useful, and I look forwards to reading more from you.benjamin wenhamhttps://www.blogger.com/profile/15079920061062261246noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-25147521258127807912015-09-12T15:26:31.615-07:002015-09-12T15:26:31.615-07:00Hi, if you're still in Seattle and are interes...Hi, if you're still in Seattle and are interested in gaming I'm getting together an group for a no-commitment open table and or drop-in game:<br /><a href="https://groups.google.com/forum/#!forum/seattle-old-school-dnd-open-table" rel="nofollow">Seattle Old School DnD Open Table</a><br />Lumhttps://www.blogger.com/profile/09490249051095856396noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-31528278644602141812015-09-11T08:29:33.724-07:002015-09-11T08:29:33.724-07:00How do you break the hex down into more hexes? Sur...How do you break the hex down into more hexes? Surely they won't fit without overlapping with another hex?RMcD94https://www.blogger.com/profile/16919280566803775512noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-72355818695175705222015-05-17T17:55:08.564-07:002015-05-17T17:55:08.564-07:00I keep coming back to this post and rereading it b...I keep coming back to this post and rereading it because it is so tracking cool and makes such sense. Thanks for it.Anonymoushttps://www.blogger.com/profile/04784778921530575525noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-48126756525673157712015-03-26T10:39:42.444-07:002015-03-26T10:39:42.444-07:00I'm sold on 6 mile hexes.
I looked up distan...I'm sold on 6 mile hexes. <br /><br />I looked up distance and I get this<br /><br />if we figure earth with an atmosphere then d= 1.32(sqrt(h))<br /><br />d=statue miles<br />h= feet.<br /><br />close enough anyways.STAR*Connect Aviationhttps://www.blogger.com/profile/14172786513198005125noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-60098242935284213072014-09-27T11:01:17.591-07:002014-09-27T11:01:17.591-07:00To me the maps in Skyrim and Oblivion seem fairly ...To me the maps in Skyrim and Oblivion seem fairly large in play but depend on both the illusion of size (I think one's real eyesight can see a lot further then the Oblivion Avatar's)and accepting that the world is rather cluttered with things. One can hike for miles in settled rural places and not come upon much more then a rusted out car or a a road. In real wilderness it's just trees and rocks for days at a time.<br /><br />In game context, you're absolutely right the density of Skyrim's encounters is far more exciting - I don't want to spend a three hour game session cross 1/2 a hex and encountering six honeybees, some deer scat and a large bay tree. <br /><br />Personally I've kind of set aside the hex map (6 mile or otherwise) for pointcrawls because of this - one can easily say X destination is 5 days on foot from Y, offer some routes and roll on the random tables as the party plans the adventure - with say a 50% of encountering something interesting each day/night cycle. This makes wilderness travel more episodic then a hex crawl, but it offsets the need to build a very dense set of hexes for me. Gus Lhttps://www.blogger.com/profile/14872819206286105195noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-67304112324415412542014-09-07T03:35:08.282-07:002014-09-07T03:35:08.282-07:00Can you suggest a graph paper that lets you do the...Can you suggest a graph paper that lets you do the 12 mile super hex well?Zombie Neighbourshttps://www.blogger.com/profile/07175770925377086853noreply@blogger.comtag:blogger.com,1999:blog-4519238203196996408.post-72644029498625832972014-07-24T14:21:18.570-07:002014-07-24T14:21:18.570-07:00Very cool, steamtunnel. I'm especially intere...Very cool, steamtunnel. I'm especially interested in the horizon calcluations. I think your recommendations might be a bit short, given the horizon calculations on the wikipedia page.<br /><br />A 1,000-foot prominence (a large hill, half the size of the smallest mountain, by one definition) is visible from 38 miles away, which is roughly 6.5 6-miles hexes.<br /><br />A 9,000-foot prominence (which is roughly the distance that Everest towers above its base camp), is visible from 19 hexes away!<br /><br />Now, all I'm doing to get these numbers is to assume that you can see anything that can see you.<br /><br />Oh, actually, I see I'm doing that wrong. According to WP, the way to tell the distance to tall objects is to add together the observer's to-the-horizon distance with that of a hypothetical, second observer, atop the thing you're trying to see.<br /><br />So if you're on a 1,000-foot prominence trying to see a 9,000 foot prominence, you can see that from 6.5+19=25.5 hexes away. (Woah.)Michael Prescotthttps://www.blogger.com/profile/04704966067758312492noreply@blogger.com